题目信息
A large flower arrangement contains 3 types of flowers: carnations, lilies, and roses. Of all the flowers in the arrangement,
are carnations,
are lilies, and
are roses. The total price of which of the 3 types of flowers in the arrangement is the greatest?



A:Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B:Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C:BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D:EACH statement ALONE is sufficient.
E:Statements (1) and (2) TOGETHER are NOT sufficient.
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正确答案:
A:Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Algebra Applied problems; Ratios
Let T be the total number of flowers, and let $C, $L, and $R be the cost, respectively, of one carnation, one lily, and one rose.
We are given that L = 3C (because C:L is 1:3) and R = 4C (because C:R is 1:4). The table below shows the total price for each type of flower.
From the table it is clear that lilies have the greatest total cost; SUFFICIENT.
We are given that R = 0.75 + C and R = 0.25 + L. To simplify matters, we can use these equations to express each of the variables C, L, and R in terms of a single fixed variable, for example, C = R −
and L = R −
. This will allow us to replace all appearances of C, L, and R with appearances of R only, thereby reducing by two the number of variables that have to be dealt with. The table below shows, for two values of T and R, the total price for each type of flower.
From the table it is clear that the type of flower having the greatest total cost can vary; NOT sufficient.
Tip Consider the expressions under “Total price” in the previous table. Note that, for a fixed value of T, as the value of R increases without bound, the total price for carnation will eventually exceed the total price for each of the other two types of flowers. Therefore, for non-sufficiency of (2), it is only necessary to determine whether there exist values for T and R such that carnations do not have the greatest total price. This suggests trying a small value for R, for example R = 1. Also, note that T = 24 was chosen to avoid fractions in the computations—24 is divisible by both 8 and 12.
The correct answer is A;statement 1 alone is sufficient.
Let T be the total number of flowers, and let $C, $L, and $R be the cost, respectively, of one carnation, one lily, and one rose.
We are given that L = 3C (because C:L is 1:3) and R = 4C (because C:R is 1:4). The table below shows the total price for each type of flower.
Flower | Number of flowers | Price per flower | Total price |
Carnation | ![]() |
C | ![]() |
Lily | ![]() |
3C | TC |
Rose | ![]() |
4C | ![]() |
From the table it is clear that lilies have the greatest total cost; SUFFICIENT.
We are given that R = 0.75 + C and R = 0.25 + L. To simplify matters, we can use these equations to express each of the variables C, L, and R in terms of a single fixed variable, for example, C = R −


Flower | Number of flowers | Price per flower | Total price | Total price: T = 24, R = 1 | Total price: T = 24, R = 10 |
Carnation | ![]() |
R − ![]() |
![]() ![]() |
3 | 111 |
Lily | ![]() |
R − ![]() |
![]() ![]() |
6 | 78 |
Rose | ![]() |
R | ![]() |
4 | 40 |
From the table it is clear that the type of flower having the greatest total cost can vary; NOT sufficient.
Tip Consider the expressions under “Total price” in the previous table. Note that, for a fixed value of T, as the value of R increases without bound, the total price for carnation will eventually exceed the total price for each of the other two types of flowers. Therefore, for non-sufficiency of (2), it is only necessary to determine whether there exist values for T and R such that carnations do not have the greatest total price. This suggests trying a small value for R, for example R = 1. Also, note that T = 24 was chosen to avoid fractions in the computations—24 is divisible by both 8 and 12.
The correct answer is A;statement 1 alone is sufficient.


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